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Grade 11Physical Chemistry

O.75 mole isothermally at 300 k from 15 l to 25 l the maximum work is

Profile image of Sabugarrafiya
8 Years agoGrade 11
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1 Answer

Profile image of Arun
8 Years ago
Dear student
 
w =  –n R T ln (V2/V1)
 
w = – 2.303 * nRT log (V2/V1)
 
w = –2.303 * 0.75 * 8.314 * 300 log (25/15)
 
on solving
w = –955.5 Joules
 
Regards
Arun (askIITians forum expert)