Physical ChemistryNumber of coulomb required to deposit 5.4 grams of aluminium when the given electrode equation is Al³+ +3e---> Al sreyaaw tallapragada 8 Years agoGrade
Arun8 Years agoDear student For one mole of Al (27 gm) requires = 3*96500 C 1 gm of Al requires = 3 *96500/27 Hence 5.4 gm requires = 3 * 96500* 5.4/27 = 57900 C Regards Arun (askIITians forum expert)