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No. of oxalic acid molecules in 100 ml of 0.02 N oxalic acid are -(a) 6.022 x 1020(b) 6.022 x 1021(c_)6.022 x 1022(d) 6.022 x 1023
As Oxalic acid is dibasic, n-factor (Basicity) = 2Now, Normality = No. of moles / n-factor / Vol in litres.So, 0.02 = n x 2/0.1 i.e. n = 0.001Thus no. of molecules = Avagadro no / No. of moles = 6.022 x 1020 molecules
Molarity=0.4Volume of oxalic acid=100mlSo,Molarity=No. Of moles solutie/volume of solution0.4=no.of moleof solute/100So, no. Of moles of solute=0.4×100/1000=0.004molesNo.of molecules of oxalic acid=no of moles of solute× avagdro no.No. Of molecules of oxalic acid=0.004×6.023×[10]23=24.184×[10]23
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