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No of atom present in 0.5 gm atom of nitrogen is same as atom in
Atomic mass of nitrogen = 14 gTherefore, mass of 1 mole of nitrogen = 14gNow, 1 mole = 6.022 x 1023 atomsSince, 1 g-atom = 1 mole0.5 g-atom = 0.5 molesTherefore, no. of atoms in 0.5 moles of Nitrogen = 6.022 x 10^23 x 0.5 = 3.011 x 10^238 g oxygen = 0.5 mole oxygenNumber of atoms in 0.5 mole oxygen =3.011 x 10^23So 8 gram of oxygen is correct answer..
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