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Name the members of the lanthanoid series which exhibit + 4 oxidation states and those which exhibit +2 oxidation states. Try to correlate this type of behavior with the electronic configuration of these elements.

Manvendra Singh chahar , 12 Years ago
Grade Upto college level
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Askiitians Tutor Team

The lanthanoid series, also known as the lanthanide series, consists of 15 elements from lanthanum (La) to lutetium (Lu). When discussing their oxidation states, it's interesting to note that certain members exhibit +4 and +2 oxidation states. Let's break this down to understand which elements fall into these categories and how their electronic configurations influence these behaviors.

Members Exhibiting +4 Oxidation States

In the lanthanoid series, the elements that can exhibit a +4 oxidation state are:

  • Ce (Cerium)
  • Pr (Praseodymium)
  • Nd (Neodymium)
  • Tb (Terbium)
  • Dy (Dysprosium)
  • Ho (Holmium)
  • Er (Erbium)
  • Tm (Thulium)
  • Yb (Ytterbium)

These elements can lose four electrons, typically from their 6s and 5d orbitals, allowing them to achieve a +4 oxidation state.

Members Exhibiting +2 Oxidation States

On the other hand, the lanthanoids that commonly exhibit a +2 oxidation state include:

  • Ce (Cerium)
  • Pr (Praseodymium)
  • Nd (Neodymium)
  • Sm (Samarium)
  • Eu (Europium)
  • Gd (Gadolinium)
  • Tb (Terbium)
  • Dy (Dysprosium)
  • Yb (Ytterbium)

These elements can lose two electrons, primarily from their 6s orbital, leading to a stable +2 oxidation state.

Understanding Electronic Configuration

The electronic configuration of lanthanoids plays a crucial role in determining their oxidation states. The general electronic configuration for lanthanides can be expressed as follows:

  • La: [Xe] 6s²
  • Ce: [Xe] 6s² 4f¹
  • Pr: [Xe] 6s² 4f³
  • Nd: [Xe] 6s² 4f⁴
  • Sm: [Xe] 6s² 4f⁵
  • Eu: [Xe] 6s² 4f⁷
  • Gd: [Xe] 6s² 4f⁷ 5d¹
  • Tb: [Xe] 6s² 4f⁹
  • Dy: [Xe] 6s² 4f¹⁰
  • Ho: [Xe] 6s² 4f¹¹
  • Er: [Xe] 6s² 4f¹²
  • Tm: [Xe] 6s² 4f¹³
  • Yb: [Xe] 6s² 4f¹⁴
  • Lu: [Xe] 6s² 4f¹⁴ 5d¹

When elements like cerium and europium exhibit +4 and +2 oxidation states respectively, it can be attributed to their ability to either lose more electrons from the 4f subshell or stabilize their configurations by losing fewer electrons. For instance, europium's +2 state is particularly stable due to its half-filled 4f subshell, which provides extra stability.

Summary of Oxidation States and Stability

In summary, the ability of lanthanoids to exhibit different oxidation states is closely tied to their electronic configurations. The +4 oxidation state is generally observed in the earlier members of the series, while the +2 state is more common in the middle to later members. This behavior highlights the intricate relationship between electron configuration and chemical properties in the lanthanoid series.

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