Grade 11Physical Chemistry
Mole fraction of solute in benzene is 0.2. Calcualte its molality of solute.need the answer very urgentlyy!!!
Mole fraction of solute in benzene is 0.2. Calcualte its molality of solute.
need the answer very urgentlyy!!!
3 Answers
Ashutosh Mohan Sharma
mole fraction = 0.2.
therefore in 100 moles, 20 moles are of solute and 80 moles are of benzene(solvent)
mass of benzene = 80 * Mol.Wt of Benzene = 80* 78 = 6240g
for 6240 g of solvent we have 20 moles of solute
Therefore for 1000g of solvent we have (20)*(1000)/(6240) = 3.20 molal
therefore in 100 moles, 20 moles are of solute and 80 moles are of benzene(solvent)
mass of benzene = 80 * Mol.Wt of Benzene = 80* 78 = 6240g
for 6240 g of solvent we have 20 moles of solute
Therefore for 1000g of solvent we have (20)*(1000)/(6240) = 3.20 molal
Aparna
no. of moles of solute/no. of moles of benzene =0.2=02/10=1/5.It means 1 mole solute in 4 moles benzeneMolality=no. of moles of solute*1000/weight of benzene in g.....(1).weight of benzene= no. of moles* molar mass=4*78=312Molality =1*1000/312=3.2 molal
Kushagra Madhukar
Dear student,
Please find the solution to your problem below.
mole fraction = 0.2.
therefore in 100 moles, 20 moles are of solute and 80 moles are of benzene(solvent)
mass of benzene = 80 * Mol.Wt of Benzene = 80* 78 = 6240g
for 6240 g of solvent we have 20 moles of solute
Therefore for 1000g of solvent we have (20)*(1000)/(6240) = 3.20 molal
Hope it helps.
Thanks for the question.
Regards,
Kushagra
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