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Molality of sulphuric acid solution is 0.2mol/kg find total weight of solution?(in gm)

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4 years ago

```							0.2 molality means0.2 moles of solute are present in 1 kg of solvent.mass of solution would be=>  mass of solute + mass of solvent.mass of solute  = molar mass * moles of solute = > 98 * 0.2 = 19.6 gmTherfore,mass of soltuion is = 1000+ 19.6 = 1019.6 gm.
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4 years ago
```							Molality= moles of solute ÷ mass of solventHence moles of solute= 0.2            Mass of solvent =1000gHence, moles of solute *Molecular mass= given massMolar mass for sulphuric acid = 98Hence, 98*0.2= 19.6g (given mass)We know Mass of solution =mass of solute + mass of solvent = 19.6+1000=1019.6g
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4 years ago
```							If the weight of solvent that is 1kg or 1000 g is given in question so we have to calculate total weight of solution..2 molal of sulphuric acidMolecular weight of h2so4 is 98g Hence weight of solute is 98g×.2=19.6gSo total weight of solution will be 1000g + 19.6g=1019.6g.ans(cheers)
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one year ago
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