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Ksp of Ag2CrO4 is 1.1 × 10 -12 at 298 K . The solubility (in moles/litre) of Ag2CrO4 is a 0.1 M AgNO3 [Please show the calculationsd also ]

Ksp of Ag2CrO4 is 1.1 × 10-12 at 298 K . The solubility (in moles/litre) of Ag2CrO4 is a 0.1 M AgNO3
[Please show the calculationsd also ]

Grade:11

1 Answers

Vikas TU
14149 Points
7 years ago
             Ag2CrO4 --------------->             2Ag+         +            CrO4-
t=0               s                                             0                                0
t=t              0                                              2s                               s
Ksp = (2s)^2 (s) => 4s^3 = 1.1 x 10^-12
s = (0.275 x 10^-12)^(1/3)
  = 0.65029 x 10^-4 mol/litre. should be the solubiity.

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