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`        Ksp of Ag2CrO4 is 1.1 × 10-12 at 298 K . The solubility (in moles/litre) of Ag2CrO4 is a 0.1 M AgNO3[Please show the calculationsd also ]`
3 years ago

Vikas TU
9797 Points
```							             Ag2CrO4 --------------->             2Ag+         +            CrO4-t=0               s                                             0                                0t=t              0                                              2s                               sKsp = (2s)^2 (s) => 4s^3 = 1.1 x 10^-12s = (0.275 x 10^-12)^(1/3)  = 0.65029 x 10^-4 mol/litre. should be the solubiity.
```
3 years ago
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