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Grade 12Physical Chemistry

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Profile image of Harshit Bhansali
6 Years agoGrade 12
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1 Answer

Profile image of Vikas TU
ApprovedApproved Tutor Answer6 Years ago
Dear student 
Fraction of energy supplied for increment in internal energy = 1/γ  = 3/5 [AS γ  = 5/3 for monoatomic gas]
Therefore,  Percentage energy = 30/5 = 60%
Fraction of energy supplied for external work done = 1 - 1/γ = γ - 1/γ = (5/3 - 1)/5/3 = 2/5
Therefore Percentage energy = 2/5 x 100% = 40%
Internal energy : work done
60% : 40%
60:40
Answer is b) 60:40