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`        Kindly refer to the image for the doubt. I cannot understand and solve this question .  `
7 months ago

Vikas TU
11137 Points
```							Dear student Fraction of energy supplied for increment in internal energy = 1/γ  = 3/5 [AS γ  = 5/3 for monoatomic gas]Therefore,  Percentage energy = 30/5 = 60%Fraction of energy supplied for external work done = 1 - 1/γ = γ - 1/γ = (5/3 - 1)/5/3 = 2/5Therefore Percentage energy = 2/5 x 100% = 40%Internal energy : work done60% : 40%60:40Answer is b) 60:40
```
7 months ago
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### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions