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Grade: 12
        
Kindly refer to the image for the doubt. 
I cannot understand and solve this question . 
 
24 days ago

Answers : (1)

Vikas TU
9098 Points
							
Dear student 
Fraction of energy supplied for increment in internal energy = 1/γ  = 3/5 [AS γ  = 5/3 for monoatomic gas]
Therefore,  Percentage energy = 30/5 = 60%
Fraction of energy supplied for external work done = 1 - 1/γ = γ - 1/γ = (5/3 - 1)/5/3 = 2/5
Therefore Percentage energy = 2/5 x 100% = 40%
Internal energy : work done
60% : 40%
60:40
Answer is b) 60:40
24 days ago
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