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Grade 12th passPhysical Chemistry

KI and sucrose solution with 0.1M concentrations osmotic pressure of 0.465atm and 0.245atm.find the bant hadd KI and it's degree of dissociation.

Profile image of Deep
6 Years agoGrade 12th pass
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1 Answer

Profile image of Vikas TU
6 Years ago
Dear Student,
Please find below the solution to the asked query.
Osmotic pressure is given as:
π = iCRT
where π = osmotic pressure
i = van't Hoff factor
C = concentration
R = Gas constant
T = Temperature
So, for KI,
0.465 = i x 0.1 RT --------------------------------(1)
and for Sucrose,
0.245 = 1 x 0.1 RT -------------------------------(2)
(for sucrose, i = 1 as it doesn't dissociate into ions in solution)
Divide equation (1) by (2)
⇒0.4650/245=0.1iRT/0.1RT⇒
i = 1.897
For KI, degree of dissociation is:
α = (i−1)/(n−1)
or 
α = 1.897−1 / 2−1=0.897
or
α = 89.7%
So, van't Hoff factor = 1.897
Degree of dissociation = 89.7%
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