Kc for the esterfication reaction : CH3COOH + C2H5OH = CH3COOC2H5 +H2O is 4. If 4 mol each of acid and alcohol are taken initially, what is the equilibrium concentration of the acid ?

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​Kc for the esterfication reaction : CH3COOH + C2H5OH = CH3COOC2H5 +H2O is 4. If 4 mol each of acid and alcohol are taken initially, what is the equilibrium concentration of the acid ?

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Kc for the esterfication reaction : CH3COOH + C2H5OH = CH3COOC2H5 +H2O is 4. If 4 mol each of acid and alcohol are taken initially, what is the equilibrium concentration of the acid ?

Kc for the esterfication reaction :
CH3COOH + C2H5OH = CH3COOC2H5 +H2O
is 4. If 4 mol each of acid and alcohol are taken initially, what is the equilibrium concentration of the acid ?

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​Kc for the esterfication reaction : CH3COOH + C2H5OH = CH3COOC2H5 +H2O is 4. If 4 mol each of acid and alcohol are taken initially, what is the equilibrium concentration of the acid ?

​Kc for the esterfication reaction :CH3COOH + C2H5OH = CH3COOC2H5 +H2O is 4. If 4 mol each of acid and alcohol are taken initially, what is the equilibrium concentration of the acid ?

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Kc for the esterfication reaction : CH3COOH + C2H5OH = CH3COOC2H5 +H2O is 4. If 4 mol each of acid and alcohol are taken initially, what is the equilibrium concentration of the acid ?

Kc for the esterfication reaction :
CH3COOH + C2H5OH = CH3COOC2H5 +H2O
is 4. If 4 mol each of acid and alcohol are taken initially, what is the equilibrium concentration of the acid ?