Grade 12th passPhysical Chemistry
ka for ch3cooh is 1.8 find out the percentage dissociation of o.2 m ch3cooh in 0.1 m hcl
ka for ch3cooh is 1.8 find out the percentage dissociation of o.2 m ch3cooh in 0.1 m hcl
1 Answer
Arun
HCl dissociated completely.
Now, let the concentration of acetate ion be x. Therefore, hydrogen ion contribution from acetic acid = x.
Since HCl dissociates completely, hydrogen ion contribution from HCl =0.1M
Total [H+] concentration = x + 0.1
Now, Ka for acetic acid = 1.8 x 10-5
Now, let the concentration of acetate ion be x. Therefore, hydrogen ion contribution from acetic acid = x.
Since HCl dissociates completely, hydrogen ion contribution from HCl =0.1M
Total [H+] concentration = x + 0.1
Now, Ka for acetic acid = 1.8 x 10-5
1.8 x 10-5 = x (x + 0.1)/0.2
on solving x = 0.35 * 10^-4
hence percentage dissociation = 0.35 * 10^-4 * 100 /0.2 = 0.0175
Hope it helps. Let us know if there is any issue.
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