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Grade: 12th pass
        
ka for ch3cooh is 1.8 find out the percentage dissociation of o.2 m ch3cooh in 0.1 m hcl
one month ago

Answers : (1)

Arun
22540 Points
							
HCl dissociated completely. 

Now, let the concentration of acetate ion be x. Therefore, hydrogen ion contribution from acetic acid = x.

Since HCl dissociates completely, hydrogen ion contribution from HCl =0.1M

Total [H+] concentration = x + 0.1

Now, Ka for acetic acid = 1.8 x 10-5
 
1.8 x 10-5  = x (x + 0.1)/0.2
on solving x = 0.35 * 10^-4
 
hence percentage dissociation = 0.35 * 10^-4 * 100 /0.2 = 0.0175  
Hope it helps. Let us know if there is any issue.
one month ago
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