In the reaction, N 2 O 4 (g) ?????? ???????? 2NO 2 (g), if D and d are the vapour densities at initial state and at equilibrium then what will be the value of at point A in the following graph. ans:(integer type ques)

Question

Sunil Kumar FP · Answer

N2O4---2NO2
here alpha is the degree of dissociation.we have to find the value of (D/d),when it is 0.When the degree of dissociation is 0,then the molecule will be consisting of N2O4 only because at that time no NO2 was formed.
so the D=vapour density at initial state=molecular formula/2=92/2=46
d=density due to N2O4
therefore D/d will be equal to 1

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In the reaction, N 2 O 4 (g) ?????? ???????? 2NO 2 (g), if D and d are the vapour densities at initial state and at equilibrium then what will be the value of at point A in the following graph. ans:(integer type ques)

In the reaction, N₂O₄(g) ?????????????? 2NO₂(g), if D and d are the vapour densities at initial state and at equilibrium then what will be the value of at point A in the following graph.

ans:(integer type ques)

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In the reaction, N 2 O 4 (g) ?????? ???????? 2NO 2 (g), if D and d are the vapour densities at initial state and at equilibrium then what will be the value of at point A in the following graph. ans:(integer type ques)

In the reaction, N2O4(g) ?????????????? 2NO2(g), if D and d are the vapour densities at initial state and at equilibrium then what will be the value of at point A in the following graph. ans:(integer type ques)

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In the reaction, N₂O₄(g) ?????????????? 2NO₂(g), if D and d are the vapour densities at initial state and at equilibrium then what will be the value of at point A in the following graph.

ans:(integer type ques)