Grade 12Physical Chemistry
In the reaction 2Na2S2O3-Na2S4O6 + 2NaI ,the equivalent weight of Na2S2O3(mol weight = M) is equal to
In the reaction 2Na2S2O3-Na2S4O6 + 2NaI ,the equivalent weight of Na2S2O3(mol weight = M) is equal to
1 Answer
Arun
Dear Rishika
2Na₂S₂O₃ + I₂ → Na₂S₄O₆ 2NaI
oxidation of S in S₂O₃⁻² = 2
oxidation number of S in S₄O₆⁻² = 5/2
oxidation number of S in S₄O₆⁻² = 5/2
again, 2S₂O₃⁻² → S₄O₆⁻²
for 2 moles of S₂O₃⁻²
change in oxidation number= 4x5/2 - 2x2x2
= 2
for 1 mole it'll be = 2/2 = 1
for 2 moles of S₂O₃⁻²
change in oxidation number= 4x5/2 - 2x2x2
= 2
for 1 mole it'll be = 2/2 = 1
∴ equivalent mass of Na₂S₂O₃
= molar mass / change in oxi. no. = 158/1 = 158
= molar mass / change in oxi. no. = 158/1 = 158
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