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`        In the analysis f 0.500 g sample of feldspar, a mixture of chlorides of sodium and potassium is obtained which weighs 0.1180g. Subsequent treatment of mixed chlorides, with silver nitrate gives 0.2451 g of silver chloride. What is the percentage of sodium oxide and potassium oxide in feldspar.`
5 years ago

```
(i) Equate given mass of AgCI against mass obtained from NaCI and KCI

(ii) 2NaCI ≡ Na­2O & 2KCI ≡ K2O

Let amount of NaCI in mixture = x gm

∴ amount of KCI in mixture = (0.118 - x) gm

NaCI + AgNO3 → AgCI + NaNO3

58.5 g 143.5 g

∵ 58.5 g NaCI gives AgCI = 143.5 g

∴ x g NaCI gives AgCI = 143.5/58.5 * x g

Again

KCI + AgNO3 → AgCI + KNO3

74.5 g 143.5 g

∵ 74.5 g KCI gives AgCI = 143.5 g

∴ (0.118 - x) g KCI gives AgCI = (143.5/74.5 * 0.118 – x)g

Total weight of AgCI = 0.2451g

∴ (143.5/58.5 * x) + [143.5/74.5 * (0.118 - x)] = 0.2451

∴ x = 0.0338g

∴ Amount of NaCI in mixture = 0.0338g

∴ Amount of KCI in mixture = 0.118 – 0.0338 = 0.0842g

Since 2NaCI ≡ Na2O

2 * 58.5 62

= 117.0

∵ 117g NaCI is equivalent = 62.0g Na2O

∴ 0.033g NaCI is equivalent to = 62.0/117 * 0.0338 g Na2O

= 0.0179g

% of Na2O in 0.5g of feldspar = 0.0179/0.500 * 100 = 3.58%

2KCI ≡ K2O

2 * 774.5 = 149 94

∵ 149g of KCI is equivalent to = 94g K2O

∴ 0.0842g of KCI is equivalent to 94/149 * 0.0842

= 0.0531 g K2O

∴ % of K2O in 0.5 of feldspar = 0.0531/0.5 * 10.62%

% of Na2O in feldspar = 3.58%

% of K2O in feldspar = 10.62%

```
5 years ago
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