in section finding n factor, in the equation KClO 3 to KCl + O 2, when we use formula ½ ax-1/2ay, we get 3 as nfactor rather than 6. how?

Question

Sakshi · Answer

Hi..
The oxidation state in the reaction changes for oxygen only.
In LHS, the oxidation state for O is -2 and that in the RHS is 0
The change in oxidation state for one oxygen is 2, thus the total change in the oxidation state for the compound is 2*3=6
So, is the answer..
Regards

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in section finding n factor, in the equation KClO 3 to KCl + O 2, when we use formula ½ ax-1/2ay, we get 3 as nfactor rather than 6. how?

in section finding n factor,

in the equation KClO₃to KCl + O_2,
when we use formula ½ ax-1/2ay, we get 3 as nfactor rather than 6. how?

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in section finding n factor, in the equation KClO 3 to KCl + O 2, when we use formula ½ ax-1/2ay, we get 3 as nfactor rather than 6. how?

in section finding n factor, in the equation KClO3 to KCl + O2,when we use formula ½ ax-1/2ay, we get 3 as nfactor rather than 6. how?

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in section finding n factor,

in the equation KClO₃to KCl + O_2,
when we use formula ½ ax-1/2ay, we get 3 as nfactor rather than 6. how?