Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
`        in an exeriment, 4 gram of M2Ox oxide was reduced to 2.8 gram of the metal.if the atomic mass of the metal is 56 gram per mole,the number of o-atoms in the oxide is`
2 years ago

## Answers : (1)

Vikas TU
8468 Points
```							moles of M2Ox => 4/(2M + 16x)and moles of M => 8/(2M + 16x)From 2.8 gm,moles of M => 2.8/MNow both should be equal hence, 2.8/M = 4/(M + 8x)0.7M = 1/(M + 8x)............(1)Now given M = 56 put the value in eqn. (1) we get,39.2 = 1/(8x + 56)(x + 7) = 1/313.6 x = 7 (approx) cant be negative.
```
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details