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in an exeriment, 4 gram of M2Ox oxide was reduced to 2.8 gram of the metal.if the atomic mass of the metal is 56 gram per mole,the number of o-atoms in the oxide is
moles of M2Ox => 4/(2M + 16x)and moles of M => 8/(2M + 16x)From 2.8 gm,moles of M => 2.8/MNow both should be equal hence, 2.8/M = 4/(M + 8x)0.7M = 1/(M + 8x)............(1)Now given M = 56 put the value in eqn. (1) we get,39.2 = 1/(8x + 56)(x + 7) = 1/313.6 x = 7 (approx) cant be negative.
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