MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
prashant kumar Grade: 12th pass
        
in an exeriment, 4 gram of M2Ox oxide was reduced to 2.8 gram of the metal.if the atomic mass of the metal is 56 gram per mole,the number of o-atoms in the oxide is
one year ago

Answers : (1)

Vikas TU
6872 Points
										
moles of M2Ox => 4/(2M + 16x)
and moles of M => 8/(2M + 16x)
From 2.8 gm,
moles of M => 2.8/M
Now both should be equal hence,
 2.8/M = 4/(M + 8x)
0.7M = 1/(M + 8x)............(1)
Now given M = 56 put the value in eqn. (1) we get,
39.2 = 1/(8x + 56)
(x + 7) = 1/313.6
 x = 7 (approx) cant be negative.
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details