in acidic medium the standard reduction potential of NO converted to n2o is 1.59 volt its Standard potential in alkaline medium at 298 Kelvin would be

Given conditions in the equation :-

NO ------→ N₂O [ E⁰ = 1.59]

Now the reaction for acidic medium :-

2NO +2H⁺ -----→ N₂O + H₂O
E⁰ =1.59

Reaction for basic medium :-

2NO + H₂O -----→ N₂O + 2OH⁻
Let E⁰ = x

Now the main reversible for alkaline medium

H₂O ⇆ H⁺ + OH⁻
= 10⁻¹⁴ .

or balanced reaction

2H₂O ⇆ 2H⁺ + 2OH⁻
= 10⁻²⁸ .


Now, The formula for calculating cell potential

E⁰cell = (0.059 /n ) log K
E⁰cell = (0.059/2) × log 10⁻²⁸
E⁰cell = (0.295) × (28)
E⁰cell = 0.826

Now for standard potential


1.59 + x = 0.826
x = 0.764

''Hence 0.764 is the required potential'