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Grade 11Physical Chemistry

In a gravimetric determination of phosphorus and aqueous solution of dihydrogen phosphate ion is treated with the mixture of ammonium and magnesium ions to precipitate magnesium Ammonium Phosphate. this is heated and decompose to magnesium pyrophosphate which is weighed. Solution of h2po4 yielded 1.054 gram of Mg2P2O7 what weight of NaH2 PO 4 was originally present?

Profile image of Shubham
8 Years agoGrade 11
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2 Answers

Profile image of arpit gaur
8 Years ago
NaH2PO4 ------» Mg2P2O7
Applying POAC on P atom, we get
2 x wt. Of Mg2P2O7/ molar mass of Mg2P2O7 = 
Wt. Of NaH2PO4/ molar mass of NaH2PO4
=» 2 x 1.054/222 = wt. Of NaH2PO4/ 120
=» wt. Of NaH2PO4 = 1.14g
So, ans. Is 1.14g
 
Profile image of ROHIT KUMAR SHARMA
7 Years ago
 
NaH2PO4 ------» Mg2P2O7
Applying POAC on P atom, we get
2 x wt. Of Mg2P2O7/ molar mass of Mg2P2O7 = 
Wt. Of NaH2PO4/ molar mass of NaH2PO4
=» 2 x 1.054/222 = wt. Of NaH2PO4/ 120
=» wt. Of NaH2PO4 = 1.14g
So, ans. Is 1.14g
 

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