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in a 13 L vessel initially following reaction occur C(s) + S 2 (g)=CS 2 (g) by 12gC, 64gS2,76gCS2 at 1027 0 C tempature then total pressure is.
Dear student Use P=nRT/VSince total pressure at equilibrium is equal to initial partial pressure of S2Ans is 100R. RegardsArun
According to ideal gas equation...PV = nRTwhere we have...V = 13 litren = 2 moles (gaseous) T = 1027°C = 1300 KP=?PV = nRTP * 13 = 2R*1300P = 200R
Pv=nRT (according to ideal gas equation) in this we have to find the value of p here v=13 litres, n=2 moles, T=1027©=1300K p×13=2R×1300 p=200R
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