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IF THERE ARE THREE POSSIBLE VALUES FOR SPIN QUANTUM NUMBER, THEN POSSIBLE NUMBER OF ELEMENTS IN THE 5TH PERIOD OF PERIODIC TABLE WOULD BE- ANS 27 HOW?? PLEASE REPLY FAST
just some enquiry about the question is the atomic number is 27 or anything else n if atomic number is 27 i.e cobalt then it would be in 4th period not 5th isnt it ??and any other correction in question u can tell ??
I in V Orbit there are 5 best holiday and V P orbital is Orbit or 1 in number and 5 power 3 in number and D orbital 5 in number then total 27 elements are there5s=1*34d=5*35p=3*3So totalno of element is 27Hope this will be true answer.....
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