Grade 11Physical Chemistry

If the shortest wave length of Lyman series of H atom is x, then the wave length of the first line Balmer series of H atom will be 1) 9x/52) 36x/53) 5x/94) 5x/36Explanation please..Thank You

Yagnesh Devada

9 Years agoGrade 11

2 Answers

Adityan

9 Years ago

The wave no. of any series is given by;

$(1/\lambda ) = 109678 * [ (1/n^{2}_{1}) - (1/n_{2}^{2}) ]$

where 109678 is a constant,lets say = $\alpha$ ;

and,the series starts from n1 to n2;

Here,x is the wavelength for the last line(shortest wavelength) in lyman series,

therefore,n₁=1 to n₂= $\bowtie$ (infinity);

$\Rightarrow$ (1/x)= $\alpha$ [(1/1) – (1/ $\bowtie$ )] = $\alpha$ (1 - 0) = $\alpha$

$\Rightarrow$ $\alpha$ = 1/x

For wavelength of first line of balmer series,

n₁=2 to n₂=3 ;lets say the wavelength to be found be = $\lambda$ ;

$\Rightarrow (1/\lambda ) = \alpha *[(1/2^{2}) - (1/3^{2})] = \alpha(5/36)$

Substituting the value

$\Rightarrow (1/\lambda ) = (5/36)(1/x) = 5/(36x) \Rightarrow \lambda =36x/5$

Ans(2)

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ankit singh

6 Years ago

For wavelength of first line of balmer series,

n₁=2 to n₂=3 ;lets say the wavelength to be found be = $\lambda$ ;

$\Rightarrow (1/\lambda ) = \alpha *[(1/2^{2}) - (1/3^{2})] = \alpha(5/36)$

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If the shortest wave length of Lyman series of H atom is x, then the wave length of the first line Balmer series of H atom will be 1) 9x/52) 36x/53) 5x/94) 5x/36Explanation please..Thank You

Yagnesh Devada

2 Answers

Adityan

ankit singh

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