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Grade 12th PassPhysical Chemistry

If the incident frequency of a radiation is doubled,then the stopping potential will be :
A)Halved
B)Doubled
C)More than doubled
D)Less than doubled

Manas Mishra

8 Years agoGrade 12th Pass

1 Answer

Khimraj

8 Years ago

The photoelectric eqn is:

hf - φ = qVs,

where, the stopping potential can be solved;

Vs = (hf - φ)/q

let f' = 2f

and work function: φ of the metal is constant.

∆Vs = Vs' - Vs = [(h*2f - φ) - (hf - φ)]/q = hf/q

while,

2Vs = 2(hf - φ))/q

so that,

∆Vs > 2Vs

meaning that if the frequency is doubled the
stopping potential, Vs increases to more than doubled.

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