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If the distance of the point P (1, - 2, 1) from the plane x + 2y - 2z = a, where a > 0, is 5, then the foot of the perpendicular from P to the plane is?

If the distance of the point P (1, - 2, 1) from the plane x + 2y - 2z = a, where a > 0, is 5, then the foot of the perpendicular from P to the plane is?

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