If power of a bulb is 80 watt and wavelength of emitted radiation is 5000 Å, find number of photons emitted per second .

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Arun · Answer

Dear student Energy of one photon = hc/lambda = 6.626* 10^-34 * 3 * 10^8 / 5000* 10^-10 = 3.976 * 10^-19 J hence number of photons emitted per second = 80 / 3.976 *10^-19 = 20.121 *10^19

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If power of a bulb is 80 watt and wavelength of emitted radiation is 5000 Å, find number of photons emitted per second .

If power of a bulb is 80 watt and wavelength of emitted radiation is 5000 Å, find number of photons emitted per second .

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If power of a bulb is 80 watt and wavelength of emitted radiation is 5000 Å, find number of photons emitted per second .

If power of a bulb is 80 watt and wavelength of emitted radiation is 5000 Å, find number of photons emitted per second .

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