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Grade: 12th pass

                        

If NaCl is dropped with 10^-3mole% of SrCl2.Calculate the number of cationic vacancies.

4 years ago

Answers : (1)

Umakant biswal
5359 Points
							
@ vatsala 
concentration of srcl2 = 10 ^ -2 mole percent 
assume we have 100 moles of nacl solution . 
then 10 ^ -3 moles of srcl is doped in it . 
1 mole of nacl is doped with 10 ^ -3 / 100 moles of srcl2 
when a na+ is replaced with sr 2+ , 1 cationic vacancies are produced . 
so, total no of cationic vacancies produced by 10 ^ -5 moles of srcl2 = 10^-5 * 6.023 * 10 ^ 23 = 6.023 * 10^18 per mole . 
HOPE IT CLEARS YOUR DOUBT 
ALL THE BEST ../
4 years ago
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