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If latent heat of fusion of pure water is 1440 cal/mol, then what will be the molal depression constant of water?

If latent heat of fusion of pure water is 1440 cal/mol, then what will be the molal depression constant of water?

Grade:12

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
8 years ago
Kf = MRTo^2 / (1000 X delta Hf)

where M = molar mass of solvent = 18 g/mole
R = 2 cal /deg/mole
delta Hf = 1440 cal/mole
To = freezing point of liquid = 0 degree C = 273 K

so Kf = 18 X 2 X 273^2 / (1000 X 1440) = 1.87

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