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`        If change in energy =3×10^-8J h=6.64×10^-34j-s and c = 3×10^8m/s then walength of light is `
3 months ago

Vikas TU
9468 Points
```							Dear student energy change , ∆E = hc/lambda where h is plank's constant , c is velocity of light and  is wavelength.here h = 6.64 × 10^-34 Jsc = 3 × 10^8 m/s and ∆E = 3 × 10^-18 J now, 3 × 10^-18 = 6.64 × 10^-34 × 3 × 10^8/lambdaor, lambda   = 6.64 × 10^-34 × 10^26= 6.64 × 10^-8 m hence, wavelength of the light is 66.4 nm
```
3 months ago
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• NCERT Solutions
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