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Grade 11Physical Chemistry

If at one atmospheric pressure the gas is spreading from 20 cm cube to 50 cm cube at constant temperature then find the final pressure

Profile image of Advika Singh
7 Years agoGrade 11
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2 Answers

Profile image of Arun
7 Years ago
Dear student
 
Boyle’s law
 
P1 * V1 = P2 * V2
 
1 * 20 = P2 * 50
 
P2 = 0.4 atm
 
Regards
Arun (askIITians forum expert)
Profile image of Khimraj
7 Years ago
As the temperature is constant
sofrom ideal gas equation
PV = constant
then
Pi*Vi = Pf*Vf
1*20 = Pf*50
so 
Pf = 0.4 atm
Hope it clears.