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if a mixture of oxygen and ozone is having the rms velocity = 12.92m/s at 300K. Calculate the mole percentage of oxygen in the mixture

if a mixture of oxygen and ozone is having the rms velocity = 12.92m/s at 300K. Calculate the mole percentage of oxygen in the mixture

Grade:8

1 Answers

Vikas TU
14149 Points
5 years ago
Let the percentage of oxygen is x so that of ozone will be 100-x. We know the formula for rms velocity is sqrt(3RT/M.W).So applying the formula we get the value of x to be 19.8%.We have to take the MW as 0.32x+48-.48x=48-.16x

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