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Grade 12th passPhysical Chemistry

if 10^-5 % react molecules is crossing over the barrier in transition state at 298 K then find out the activation barrier needed to cross the transition state?

Profile image of Shahnawaz
7 Years agoGrade 12th pass
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1 Answer

Profile image of Arun
6 Years ago
Activation energy of forward reaction =0.12−0.02=0.10 kcal
Fraction of molecules which are active or which crossover the energy barrier ( 
A
k
​ 
 )=e 
−E/RT
 
log 
e
​ 
 ( 
A
k
​ 
 )=− 
RT
E
​ 
 
A
k
​ 
 =antilog[ 
2.303RT
−E
​ 
 ]
                 =antilog[ 
2.303×2×325
−0.10×1000
​ 
 ]
                 =antilog[−0.06680]=0.8574
∴ Percentage of reactant molecules crossing over the barrier =0.8574×100=85.74