Grade 11Physical Chemistry
If 10^21 molecules are removed from 200mg Of Co2. How many moles will be left?
2 Answers
Himanshu
No of moles of CO2 initially = weight of substance(gm)/ molecular mass
No.of moles of CO2 initially = 0.2/44 = 1/220 mol
No. of moles removed = no. of molecules/ avagardo constant
No. of moles removed = 1021/ (6 × 1023) = 1/600 mol
No. of moles left = 1/220 – 1/600 = 0.028 (approx.)
Kushagra Madhukar
Dear student,
Please find the solution to your problem.
No of moles of CO2 initially = mass of CO2(gm)/ molecular mass
No.of moles of CO2 initially = 0.2/44 = 1/220 mol = 4.5454 x 10-3 mol
No. of moles removed = no. of molecules/ avagardo constant
No. of moles removed = 1021/ (6.022 × 1023) = 1.6606 x 10-3 mol
No. of moles left = 4.5454 x 10-3 – 1.6606 x 10-3 = 0.00288 moles (approx.)
Thanks and regards,
Kushagra
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