I2 (aq)+l^-(aq)I^-3(aq). We start with 1 mole of I2 and 0.5 mole of I- in 1 litre flask after equilibrium is reached excess of AgNO3 gave 0.25 mole of yellow precipitate equilibrium constant is:A.1.33B. 2.66C. 2.0D.3.0
akash
8 Years agoGrade 12th pass
1 Answer
Arun
8 Years ago
Dear Akash
Keq=[I 3]/[I 2][I -]
=0.25/(0.25)(0.75)
=1/0.75
=1.33
This happens because of the following reaction-
I 3 +3AgNo3 ------>3AgI + 3No3 when I 3 reacts with AgNo 3 it gives yellow precipitate of AgI.