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I want solution of question no.62. I want solution of question no.62.
firstwe have to solve given % to get empirical formula CH3Onow we have to use idealgas eq to get mwt of compound 62nowmolecular formula of compound is (CH3O)nn=mwt/empirical wt=62/31=2finally the compound is C2H6O2
how did you get mwt of compound 62.please explain.
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