Grade 11Physical Chemistry
i am having a doubt with this sum plzzzzzzzzzzzzzz solve it
1 Answer
Arun
Dear Yash
Let the mixture contain a,b and c as C3H8, CH4 and CO.
a + b + c =100 mL
a = 36.5 ml
b+c = 100mL-36.5 mL
Burning in excess of air, following reactions takes place :
C3H8 + 5O2 → 3CO2 + 4 H2O
CH4 + 2O2 → CO2 + 2 H2O
CO + 1/2O2 → CO2
CO2 formed in terms of mole = 3a +b + c
By putting the value of a we get :
= 3 x 36.5 mL +(b+c)
= 3 x 36.5mL + (100-36.5mL)
= 173 mL
a + b + c =100 mL
a = 36.5 ml
b+c = 100mL-36.5 mL
Burning in excess of air, following reactions takes place :
C3H8 + 5O2 → 3CO2 + 4 H2O
CH4 + 2O2 → CO2 + 2 H2O
CO + 1/2O2 → CO2
CO2 formed in terms of mole = 3a +b + c
By putting the value of a we get :
= 3 x 36.5 mL +(b+c)
= 3 x 36.5mL + (100-36.5mL)
= 173 mL
Regards
Arun (askIITians forum expert)
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