Hydrolysis of sucrose give sucrose+h2o=glucose.Equilibrim constant ke for the relation 1×300k.Calculate ∆C1°at 130k

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Arun · Answer

The change in Gibb’s free energy is related to the equilibrium constant as:- G=-RTln(K). Putting the given values in the above equation, we get G=-2.303RTlog(1 x 300) Put the values and you will get the answer.

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Hydrolysis of sucrose give sucrose+h2o=glucose.Equilibrim constant ke for the relation 1×300k.Calculate ∆C1°at 130k

Hydrolysis of sucrose give sucrose+h2o=glucose.Equilibrim constant ke for the relation 1×300k.Calculate ∆C1°at 130k

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Hydrolysis of sucrose give sucrose+h2o=glucose.Equilibrim constant ke for the relation 1×300k.Calculate ∆C1°at 130k

Hydrolysis of sucrose give sucrose+h2o=glucose.Equilibrim constant ke for the relation 1×300k.Calculate ∆C1°at 130k

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