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Human body requires 2370K.cal of energy daily. If the heat of combustion of glucose is 790K.cal/mole the amount of glucose required for daily consumption is

 Human body requires 2370K.cal of energy daily. If the heat of combustion of glucose is 790K.cal/mole the amount of glucose required for daily consumption is

Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago

C6H12O6 + 9O2→ 6CO2 + 6H2O

 
This is the heat of combustion reaction for sugar.
For 1 mol it is -2370 Kcal.
For 2370 Kcal total moles would be => 2370/790 => 3 moles.
Weight of sugar => 3*180 = 540

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