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`        	How to solve q. 6. How do we find the rate of effusion of a mixture of gases?`
one year ago

```							Solution:- Rate of diffusion is inversely proportional to the square root of molar mass.Molar mass of hydrogen is 2 gram per mol and let's say the molar mass of the mixture of the two gases is M. From given data, hydrogen gas diffuses 4 times as rapidly as a mixture of ethene and carbon dioxide. The formula is written as: rH2 / rmix = sqrt (Mmix / MH2)  The ratio of rates of diffusion of hydrogen and the mixture of the gases is 4. Let's plug in the values in the formula: 4 = sqrt (M/2)doing square to both sides:M = 2(16)M = 32So, the molar mass of the mixture of ethene and carbon dioxide is 32 gram per mol.
```
one year ago
```							Rate of diffusion is inversely proportional to the square root of molar mass.Molar mass of hydrogen is 2 gram per mol and let's say the molar mass of the mixture of the two gases is M. From given data, hydrogen gas diffuses 4 times as rapidly as a mixture of ethene and carbon dioxide. The formula is written as:r H2 / r mix = sqrt( Mmix / M H2  )The ratio of rates of diffusion of hydrogen and the mixture of the gases is 4. Let's plug in the values in the formula:4 = sqrt (M/2)doing square to both sides:16 = M/2M = 2(16)M = 32So, the molar mass of the mixture of ethene and carbon dioxide is 32 gram per mol.
```
one year ago
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