Grade 12th passPhysical Chemistry
- How to solve q. 6. How do we find the rate of effusion of a mixture of gases?
- How to solve q. 6. How do we find the rate of effusion of a mixture of gases?
2 Answers
Arun
Solution:- Rate of diffusion is inversely proportional to the square root of molar mass.
Molar mass of hydrogen is 2 gram per mol and let's say the molar mass of the mixture of the two gases is M.
From given data, hydrogen gas diffuses 4 times as rapidly as a mixture of ethene and carbon dioxide. The formula is written as:
Molar mass of hydrogen is 2 gram per mol and let's say the molar mass of the mixture of the two gases is M.
From given data, hydrogen gas diffuses 4 times as rapidly as a mixture of ethene and carbon dioxide. The formula is written as:
rH2 / rmix = sqrt (Mmix / MH2)
The ratio of rates of diffusion of hydrogen and the mixture of the gases is 4. Let's plug in the values in the formula:
4 = sqrt (M/2)
doing square to both sides:
M = 2(16)
M = 32
So, the molar mass of the mixture of ethene and carbon dioxide is 32 gram per mol.
M = 32
So, the molar mass of the mixture of ethene and carbon dioxide is 32 gram per mol.
Vikas TU
Rate of diffusion is inversely proportional to the square root of molar mass.
Molar mass of hydrogen is 2 gram per mol and let's say the molar mass of the mixture of the two gases is M.
From given data, hydrogen gas diffuses 4 times as rapidly as a mixture of ethene and carbon dioxide. The formula is written as:
r H2 / r mix = sqrt( Mmix / M H2 )
The ratio of rates of diffusion of hydrogen and the mixture of the gases is 4. Let's plug in the values in the formula:
4 = sqrt (M/2)
doing square to both sides:
16 = M/2
M = 2(16)
M = 32
So, the molar mass of the mixture of ethene and carbon dioxide is 32 gram per mol.
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