soliha noor
Last Activity: 9 Years ago
If stearic no. =2 hybridisation is sp,,
=3 sp2
=4 sp3
=5 sp3d
=6 sp3d2
=7 sp3d3
If we take the example of carbon dioxide the no. of bond pairs{sigma} around carbon are 2 and there is no lone pair on carbon...so the stearic no. comes out to be 2+o=2 and thus hybridisation is sp..........If we another example of BrF4-{overall charge is -} , total no. of bond pairs around Br are 4 and lone pairs are 2 {because remaining electrons are 3 + 1 electron due to -ive charge constitute 4 electrons in total which is equal to 2 lone pairs} ..thus stearic no.=6,,hybridisation =sp3d2
