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Balancing the equation :
2C + 3H2 → C2H6 ..............ΔH(1)= -84.67 kJ/mol
2C(graphite) → 2C(g) ........ ΔH(2)= 716.7 x 2 kJ/mol
3H2→ 6H (g).......................ΔH(3)=435.9 x 3 kJ/mol
Adding the above equations and their enthalpies :
C2H6 → 2C(g) + 6H(g) ΔH(4)= 2828.4 kJ/mol
ΔH(4) = ΔH (C-C) +ΔH ( C-H)
ΔH (C-C) = ΔH(4) - ΔH ( C-H)
ΔH (C-C) = [2828.4-6 X 414.22] = 343.08 KJ/mol
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