Grade 11Physical Chemistry
How to Calculate the Molarity of 13% H2SO4 solution?
How to Calculate the Molarity of 13% H2SO4 solution?
1 Answer
Arun
Dear Student
Take exactly 1.0L = 1000mL of this solution
Mass of this solution = 1020g - from density
Solution is 13% H2SO4 by mass
Mass of H2SO4 = 13/100*1020 = 132.6g H2SO4
molarity :
Molar mass H2SO4 = 98g/mol
mol H2SO4 in 132.6g = 132.6/98 = 1.35 mol H2SO4 dissolved in 1.0L solution
Molarity = 1.35M
Should be written as 1.4M because of 2 significant figures.
Mass of this solution = 1020g - from density
Solution is 13% H2SO4 by mass
Mass of H2SO4 = 13/100*1020 = 132.6g H2SO4
molarity :
Molar mass H2SO4 = 98g/mol
mol H2SO4 in 132.6g = 132.6/98 = 1.35 mol H2SO4 dissolved in 1.0L solution
Molarity = 1.35M
Should be written as 1.4M because of 2 significant figures.
Regards
Arun (askIITians forum expert)
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