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```
how to balance following redox reaction in basic medium. C 4 H 4 O 6 2- +ClO 3 - =CO 3 2- +Cl - Please, balance with complete steps.
how to balance  following redox reaction in basic medium.C4H4O62- +ClO3- =CO32- +Cl-                      Please, balance with complete steps.

```
4 years ago

Prachi
29 Points
```							Balance
C4H4O62- + ClO31- = 4CO32- + Cl1-
C4 = +6        Cl = +5    4C = +16  Cl = -1
Hence from the above calculation of oxidation no. C shows oxidation by 10 and Cl undergoes reduction by
6. Now multiply oxidation by 3 i.e 10x3 and reduction by 5 i.e. 6x5.
3C4H4O62- + 5ClO31-  =  12CO32- + 5Cl1-
charge (-11)                        (-29)
Since basic medium thus add 18OH-  on the left side
3C4H4O62- + 5ClO31-
```
4 years ago
Prachi
29 Points
```							3C4H4O62- + 5ClO31- + 18OH- =  12CO32- + 5Cl-[ H = 30, O = 51]                                      [ H = 0, O = 36] Due to deficiency of hydrogen and oxygen on right side we add 15H2O on the right sideFinal ans.3C4H4O62- + 5ClO31-  18OH- =  12CO32- + 5Cl- + 15H2O
```
4 years ago
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