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Grade: 12th pass

                        

how to balance following redox reaction in basic medium. C 4 H 4 O 6 2- +ClO 3 - =CO 3 2- +Cl - Please, balance with complete steps.

4 years ago

Answers : (2)

Prachi
29 Points
							
Balance 
C4H4O62- + ClO31- = 4CO32- + Cl1-
C= +6        Cl = +5    4C = +16  Cl = -1
Hence from the above calculation of oxidation no. C shows oxidation by 10 and Cl undergoes reduction by
6. Now multiply oxidation by 3 i.e 10x3 and reduction by 5 i.e. 6x5.
3C4H4O62- + 5ClO31-  =  12CO32- + 5Cl1-
  charge (-11)                        (-29)
Since basic medium thus add 18OH on the left side
3C4H4O62- + 5ClO31-
4 years ago
Prachi
29 Points
							
3C4H4O62- + 5ClO31- + 18OH=  12CO32- + 5Cl-
[ H = 30, O = 51]                                      [ H = 0, O = 36] 
Due to deficiency of hydrogen and oxygen on right side we add 15H2O on the right side
Final ans.
3C4H4O62- + 5ClO31-  18OH=  12CO32- + 5Cl+ 15H2O
4 years ago
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