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Grade: 12th pass 

                        
how to balance following redox reaction in basic medium. C 4 H 4 O 6 2- +ClO 3 - =CO 3 2- +Cl - Please, balance with complete steps.
4 years ago

Answers : (2)

Prachi
29 Points 
							
Balance 


C4H4O62- + ClO31- = 4CO32- + Cl1-


C4 = +6        Cl = +5    4C = +16  Cl = -1

Hence from the above calculation of oxidation no. C shows oxidation by 10 and Cl undergoes reduction by

6. Now multiply oxidation by 3 i.e 10x3 and reduction by 5 i.e. 6x5.


3C4H4O62- + 5ClO31-  =  12CO32- + 5Cl1-


  charge (-11)                        (-29)


Since basic medium thus add 18OH-  on the left side


3C4H4O62- + 5ClO31-
4 years ago
Prachi
29 Points 
							
3C4H4O62- + 5ClO31- + 18OH- =  12CO32- + 5Cl-
[ H = 30, O = 51]                                      [ H = 0, O = 36] 
Due to deficiency of hydrogen and oxygen on right side we add 15H2O on the right side
Final ans.
3C4H4O62- + 5ClO31-  18OH- =  12CO32- + 5Cl- + 15H2O
4 years ago
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