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how to balance following redox reaction in basic medium. C 4 H 4 O 6 2- +ClO 3 - =CO 3 2- +Cl - Please, balance with complete steps. how to balance following redox reaction in basic medium.C4H4O62- +ClO3- =CO32- +Cl- Please, balance with complete steps.
Balance C4H4O62- + ClO31- = 4CO32- + Cl1- C4 = +6 Cl = +5 4C = +16 Cl = -1 Hence from the above calculation of oxidation no. C shows oxidation by 10 and Cl undergoes reduction by 6. Now multiply oxidation by 3 i.e 10x3 and reduction by 5 i.e. 6x5. 3C4H4O62- + 5ClO31- = 12CO32- + 5Cl1- charge (-11) (-29) Since basic medium thus add 18OH- on the left side 3C4H4O62- + 5ClO31-
3C4H4O62- + 5ClO31- + 18OH- = 12CO32- + 5Cl-[ H = 30, O = 51] [ H = 0, O = 36] Due to deficiency of hydrogen and oxygen on right side we add 15H2O on the right sideFinal ans.3C4H4O62- + 5ClO31- 18OH- = 12CO32- + 5Cl- + 15H2O
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