how much of naoh is required to neutralise 1500 cm3 of 0.1n hcl

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Arun · Answer

Weight of NaOH = N* E.w. * V/1000 Put the values in the above formula Weight of NaOH required.= 0.1 *40 *1500/1000 = 6 gm Hope it helps

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how much of naoh is required to neutralise 1500 cm3 of 0.1n hcl

how much of naoh is required to neutralise 1500 cm3 of 0.1n hcl

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how much of naoh is required to neutralise 1500 cm3 of 0.1n hcl

how much of naoh is required to neutralise 1500 cm3 of 0.1n hcl

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