Grade upto college level Physical Chemistry
How many millilitres of 0.5 M H2SO4 are needed to dissolve 0.5 g of copper (II) carbonate?
4 Answers
Aditi Chauhan
Sol . The balanced chemical reaction is :
CuCO3 + H2SO4 → CuSO4 + H2O + CO2
Millimol of CuCO3 = (0.5 × 1000)/123.5
= 4.048
⇒ millimol of H2SO4 required = 4.048
∵ millimol = Molarity × Volume (in mL)
⇒ Vol = 4.048/0.50 = 8.1 mL
mayank
Sol . The balanced chemical reaction is : CuCO3 + H2SO4 → CuSO4 + H2O + CO2 Millimol of CuCO3 = (0.5 × 1000)/123.5 = 4.048 ⇒ millimol of H2SO4 required = 4.048 ∵ millimol = Molarity × Volume (in mL) ⇒ Vol = 4.048/0.50 = 8.1 mL
Ashwin Sheoran
balanced chemical reaction is :
CuCO3 + H2SO4 → CuSO4 + H2O + CO2
Millimol of CuCO3 = (0.5 × 1000)/123.5
= 4.048
⇒ millimol of H2SO4 required = 4.048
∵ millimol = Molarity × Volume (in mL)
⇒ Vol = 4.048/0.50 = 8.1 mL
CuCO3 + H2SO4 → CuSO4 + H2O + CO2
Millimol of CuCO3 = (0.5 × 1000)/123.5
= 4.048
⇒ millimol of H2SO4 required = 4.048
∵ millimol = Molarity × Volume (in mL)
⇒ Vol = 4.048/0.50 = 8.1 mL
Rishi Sharma
Dear Student,
Please find below the solution to your problem.
The balanced chemical reaction is :
CuCO3 + H2SO4 → CuSO4 + H2O + CO2
Millimol of CuCO3 = (0.5 × 1000)/123.5
= 4.048
⇒ millimol of H2SO4 required
= 4.048
∵ millimol = Molarity × Volume (in mL)
⇒ Vol = 4.048/0.50
= 8.1 mL
Thanks and Regards
Please find below the solution to your problem.
The balanced chemical reaction is :
CuCO3 + H2SO4 → CuSO4 + H2O + CO2
Millimol of CuCO3 = (0.5 × 1000)/123.5
= 4.048
⇒ millimol of H2SO4 required
= 4.048
∵ millimol = Molarity × Volume (in mL)
⇒ Vol = 4.048/0.50
= 8.1 mL
Thanks and Regards
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