Yash Chourasiya
Last Activity: 4 Years ago
Dear Student
Initial pH = 1, i.e. [H+] = 0.1 mole/litre
New pH = 2, i.e. [H+] = 0.01 mole/litre
In case of dilution: M1V1 = M2V2
0.1 ×1 =0.01 × V2
V2= 10 litre.
Volume of water added = 10 – 1 = 9 litre
I hope this answer will help you.
Thanks & Regards
Yash Chourasiya