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How many litre of at by the oxidation of NaCl with 10g ? a) 3.54l b) 7.08l c) 1.77l d) None of these

How many litre of Cl_2 at STP \:will\: be\: liberatedSTP will\: be\: liberated by the oxidation of NaCl with 10g KMnO_4 ?

a) 

3.54l

 b) 

7.08l
c) 

1.77l

 d) 

None of these
 

Grade:12

2 Answers

Arun
25750 Points
4 years ago
10 NaCl + 2 KMnO4 ----------> 5 Cl2 + side products

2X 158=316 g 5 x 22.4 at S.T.P.

316 g KMnO4 gives Cl2= 5 x 22.4

10 g KMnO4 gives Cl2= 5 x 22.4 x 10/316

= 3.5 litre
Khimraj
3007 Points
4 years ago
Dear frnd... !!!

H+

10 NaCl + 2 KMnO4 ----------> 5 Cl2 + side products

2X 158=316 g 5 x 22.4 at S.T.P.

316 g KMnO4 gives Cl2= 5 x 22.4

10 g KMnO4 gives Cl2= 5 x 22.4 x 10/316

= 3.5 litre

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