Grade 12Physical Chemistry
How many litre of at
by the oxidation of NaCl with 10g
?
| a) 3.54l | b) 7.08l |
| c) 1.77l | d) None of these |
2 Answers
Arun
10 NaCl + 2 KMnO4 ----------> 5 Cl2 + side products
2X 158=316 g 5 x 22.4 at S.T.P.
316 g KMnO4 gives Cl2= 5 x 22.4
10 g KMnO4 gives Cl2= 5 x 22.4 x 10/316
= 3.5 litre
2X 158=316 g 5 x 22.4 at S.T.P.
316 g KMnO4 gives Cl2= 5 x 22.4
10 g KMnO4 gives Cl2= 5 x 22.4 x 10/316
= 3.5 litre
Khimraj
Dear frnd... !!!
H+
10 NaCl + 2 KMnO4 ----------> 5 Cl2 + side products
2X 158=316 g 5 x 22.4 at S.T.P.
316 g KMnO4 gives Cl2= 5 x 22.4
10 g KMnO4 gives Cl2= 5 x 22.4 x 10/316
= 3.5 litre
H+
10 NaCl + 2 KMnO4 ----------> 5 Cl2 + side products
2X 158=316 g 5 x 22.4 at S.T.P.
316 g KMnO4 gives Cl2= 5 x 22.4
10 g KMnO4 gives Cl2= 5 x 22.4 x 10/316
= 3.5 litre
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