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# How many ions of copper wil be deposited by half Faraday of electricity through an aqueous solution of CuSO4

3 years ago

Deepak Kumar
24 Points
CuSO4 has Cu2+ ion. So, for 1 mole of CuSO4, we will have 1 mole of Cu2+ and for that we will need 2F charge to completely reduce it to Cu.  Cu2+  +  2e-   ---->  Cu   So by given condition,2F charge reduce 1 mole of Cu2+ ion So 0.5F charge will reduce,.   1/2*0.5 = 0.25 mole of Cu2+ ionSo , no. Of ion = 0.25* 6.022* 10^23 = 1.5055* 10^23

3 years ago
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