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How many ions of copper wil be deposited by half Faraday of electricity through an aqueous solution of CuSO4

How many ions of copper wil be deposited by half Faraday of electricity through an aqueous solution of CuSO4

Grade:12

1 Answers

Deepak Kumar
24 Points
6 years ago
CuSO4 has Cu2+ ion. So, for 1 mole of CuSO4, we will have 1 mole of Cu2+ and for that we will need 2F charge to completely reduce it to Cu. Cu2+ + 2e- ----> Cu So by given condition,2F charge reduce 1 mole of Cu2+ ion So 0.5F charge will reduce,. 1/2*0.5 = 0.25 mole of Cu2+ ionSo , no. Of ion = 0.25* 6.022* 10^23 = 1.5055* 10^23

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