Grade 12th passPhysical ChemistryHow many cc of oxygen will be liberated by 2 ampere current flowing for 3 minutes and 13 seconds through acidulated water Nimra 8 Years agoGrade 12th pass
Arun8 Years agoDear student Q = 2 * 193 C = 386 C H2O ---------> H2 + ½ O2 O2 – -------> ½ O2 + 2 e- 2F = 2* 96500 C givesO2 = ½ mole = 11200 cc hence 386 C will give O2 = 11200 * 386 / (2 * 96500) = 22.4 cc RegardsArun (askIITians forum expert)