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# How many atoms are present in 11.2 L of chlorine at STP?(a) Na/2(b) Na/3(c-)Na(d) Na / 1020

Arun Kumar IIT Delhi
7 years ago
Hi Vardhan,
Its a common value please remember it
Molar Volume of gas at STP=22.4L

So 1/2 mole => Na/2

Thanks & Regards

Arun Kumar

IIT Delhi

Manas Satish Bedmutha
22 Points
7 years ago
At STP, every 1 mole gas occupies, 22.4 L, i.e. equivalent to NA molecules.
Hence, 11.2 L will have NA x (11.2 / 22.4) = NA /2 molecules.
Option (a) is correct
Zoya rajput
11 Points
4 years ago
The answer is (c) Na because Na/2 molecules of cl2 are present. but as every molecule of Cl has 2 atoms, hence there are Na/2 *2 atoms ,i.e, Na atoms.
SAM
11 Points
3 years ago
1 mole of cl2 at STP is 22.4l
Therefore 11.2l of cl2 is obtained from 0.5 moles of cl2
This implies that there are 2×0.5×NA atoms of cl.
Ans is NA
(Suprized to see that all the answers are incorrect cl is in gaseous state therefore we will take cl as
Cl2)