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Grade: 12
        
How many atoms are present in 11.2 L of chlorine at STP?
(a) Na/2
(b) Na/3
(c-)Na
(d) Na / 1020
4 years ago

Answers : (4)

Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
							Hi Vardhan,
Its a common value please remember it
Molar Volume of gas at STP=22.4L

So 1/2 mole => Na/2


Thanks & Regards

Arun Kumar

IIT Delhi

Askiitians Faculty

4 years ago
Manas Satish Bedmutha
22 Points
							
At STP, every 1 mole gas occupies, 22.4 L, i.e. equivalent to NA molecules.
Hence, 11.2 L will have NA x (11.2 / 22.4) = NA /2 molecules.
Option (a) is correct
4 years ago
Zoya rajput
11 Points
							The answer is (c) Na because Na/2 molecules of cl2 are present. but as every molecule of Cl has 2 atoms, hence there are Na/2 *2 atoms ,i.e, Na atoms.
						
one year ago
SAM
11 Points
							
1 mole of cl2 at STP is 22.4l
Therefore 11.2l of cl2 is obtained from 0.5 moles of cl2
This implies that there are 2×0.5×NA atoms of cl.
Ans is NA
(Suprized to see that all the answers are incorrect cl is in gaseous state therefore we will take cl as
Cl2)
3 months ago
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