Grade upto college level Physical Chemistry
How do you explain the absence of aldehyde group in pentaacetate of glucose?
1 Answer
Gaurav
Hello Student
D-glucose reacts withhydroxylamine (NH2OH) to form an oxime because of the
presence of aldehydic (-CHO) group or carbonyl carbon. Thishappens as the cyclic structure of glucose forms an open chainstructure in an aqueous medium, which then reacts with NH2OH to give an oxime.
But pentaacetate of
D-glucose does not react with NH2OH. This is becausepentaacetate does not form an open chain structure.
D-glucose reacts withhydroxylamine (NH2OH) to form an oxime because of the
presence of aldehydic (-CHO) group or carbonyl carbon. Thishappens as the cyclic structure of glucose forms an open chainstructure in an aqueous medium, which then reacts with NH2OH to give an oxime.
But pentaacetate of
D-glucose does not react with NH2OH. This is becausepentaacetate does not form an open chain structure.
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